2道分式加减法。(2/3a²)+(3/4b)-(5/6ab)=?(a+2b/a-b)+(b/b-a)-(2a/a-b)=?
2个回答
2011-03-26 · 知道合伙人教育行家
关注
展开全部
2/(3a^2)+3/(4b)-5/(6ab)
=2*4b/(12a^2b)+3*3a^2/(12a^2b)-5*2a/(12a^2b)
=(9a^2-10a+8b)/(12a^2b)
(a+2b)/(a-b)+ b/(b-a)- 2a/(a-b)
=(a+2b)/(a-b)- b/(a-b)- 2a/(a-b)
={(a+2b)- b- 2a}/(a-b)
=-(a+b)/(a-b)
=2*4b/(12a^2b)+3*3a^2/(12a^2b)-5*2a/(12a^2b)
=(9a^2-10a+8b)/(12a^2b)
(a+2b)/(a-b)+ b/(b-a)- 2a/(a-b)
=(a+2b)/(a-b)- b/(a-b)- 2a/(a-b)
={(a+2b)- b- 2a}/(a-b)
=-(a+b)/(a-b)
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询