Question

若|x-1|+(y+3)2次方+(z-2)4次方=0,求(x+y+z)2次方-xy-yz的值.(要有过程)

Answer 1

|x-1|+(y+3)2次方+(z-2)4次方=0
则x-1=0 y+3=0 z-2=0
x=1 y=-3 z=2

(x+y+z)2次方-xy-yz
=(1-3+2)2次方-1*(-3)-(-3)*2
=0+3+6
=9

Answer 2

|x-1|+(y+3)2次方+(z-2)4次方=0
解：|x -1|=0 x-1=0 , x=1 :
(y+3)^2=0 y+3=0 , y=-3 ;
(z -2)^4=0 z-2=0 , z=2;
(x+y+z)^2- xy - yz
=(1-3+2)^2 - 1X(-3) - (-3)X2
=0+3+6
=9