
4个回答
展开全部
(3x-2y+z)(3x+2y-z)
=[3x-(2y-z)] [3x+(2y-z)]
=(3x)² - (2y-z)²
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=[3x-(2y-z)] [3x+(2y-z)]
=(3x)² - (2y-z)²
如有帮助请采纳,手机则点击右上角的满意,谢谢!!
展开全部
(3x-2y+z)(3x+2y-z)
=
(3x-(2y-z))(3x+2y-z)
=(3x)²-(2y-z)²
=9x²-(4y²-4yz+z²)
=9x²-4y²+4yz-z²
=
(3x-(2y-z))(3x+2y-z)
=(3x)²-(2y-z)²
=9x²-(4y²-4yz+z²)
=9x²-4y²+4yz-z²
展开全部
(3x-2y+z)(3x+2y-z)
=【3x-(2y-z)】【3x+(2y-z)】
=(3x)² - (2y-z)²
=9x² -
=【3x-(2y-z)】【3x+(2y-z)】
=(3x)² - (2y-z)²
=9x² -
展开全部
解:(3x-2y+z)(3x+2y-z)
=[3x-(2y-z)][3x+(2y-z)]
=9x^2-(2y-z)^2
=[3x-(2y-z)][3x+(2y-z)]
=9x^2-(2y-z)^2
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