Question

如何让servlet弹出对话框并跳转

Answer 1

out.println("<script language = javascript>alert('aaaa')");
out.println("window.history.go(-1)</script>"); 这个是处理出错的情况弹出对话框并跳转到原来的位置的，不出错的你加个跳转语句再改下吧

Answer 2

response.setContentType("application/octet-stream");
response.addHeader("Content-Disposition", "attachment;filename=aa");
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