Question

java中怎么截取字符串最后面的4个字符

Answer 1

BattleMacross正确，传一个参数就可以了，不需要其他人那么繁琐了

Answer 2

String s = "jljfskjflsjdflksjdf";
String sub = s.subString(s.length ()- 4,s.length()); //闹告旦最友尺后四个字液扰符

Answer 3

public static void main(String[] args){

String str = "肆羡happy";
String strLast;
strLast = str.substring(str.length()-4);
System.out.println(strLast);

}
输出结果为仿做：裂大拍appy

Answer 4

package test;

public class SplitLast4 {

/**
* @param args
* @throws UnsupportedEncodingException
*/
public static void main(String[] args){
// TODO Auto-generated method stub
String s = "ghj";
String str = new SplitLast4().splitLastFourChars(s);
System.out.println(str);
}
String splitLastFourChars(String s){
String str = "";
if(s.length()<4){
return s;
}else{
for(int i=s.length()-4;i<s.length();i++){
str = str + s.charAt(i);
}
return str;
}
}
}

Answer 5

String s = "111sdfsdfsdfsfsaaxiahello啊";
String s1 = s.substring(s.length()-4,s.length());
System.out.println(s1);