求助::C# 写得 货币转换。用这个语言格式写得, 非常感谢!采纳后追加15分!
usingSystem.ComponentModel;usingSystem.Data;usingSystem.Drawing;usingSystem.Text;usin...
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Text;
using System.Windows.Forms;
namespace huob
{
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
private void Form1_Load(object sender, EventArgs e)
{
}
}
} 展开
using System.Data;
using System.Drawing;
using System.Text;
using System.Windows.Forms;
namespace huob
{
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
private void Form1_Load(object sender, EventArgs e)
{
}
}
} 展开
2个回答
展开全部
public static string CmycurD(decimal num)
{
string str1 = "零壹贰叁肆伍陆柒捌玖"; //0-9所对应的汉字
string str2 = "万仟佰拾亿仟佰拾万仟佰拾元角分"; //数字位所对应的汉字
string str3 = ""; //从原num值中取出的值
string str4 = ""; //数字的字符串形式
string str5 = ""; //人民币大写金额形式
int i; //循环变量
int j; //num的值乘以100的字符串长度
string ch1 = ""; //数字的汉语读法
string ch2 = ""; //数字位的汉字读法
int nzero = 0; //用来计算连续的零值是几个
int temp; //从原num值中取出的值
num = Math.Round(Math.Abs(num),2); //将num取绝对值并四舍五入取2位小数
str4 = ((long)(num*100)).ToString(); //将num乘100并转换成字符串形式
j = str4.Length; //找出最高位
if (j > 15){return "溢出";}
str2 = str2.Substring(15-j); //取出对应位数的str2的值。如:200.55,j为5所以tr2=佰拾元角分
//循环取出每一位需要转换的值
for(i=0;i<j;i++)
{
str3 = str4.Substring(i,1); //取出需转换的某一位的值
temp = Convert.ToInt32(str3); //转换为数字
if (i != (j-3) && i != (j-7) && i != (j-11) && i != (j-15))
{
//当所取位数不为元、万、亿、万亿上的数字时
if (str3 == "0")
{
ch1 = "";
ch2 = "";
nzero = nzero + 1;
}
else
{
if(str3 != "0" && nzero != 0)
{
ch1 = "零" + str1.Substring(temp*1,1);
ch2 = str2.Substring(i,1);
nzero = 0;
}
else
{
ch1 = str1.Substring(temp*1,1);
ch2 = str2.Substring(i,1);
nzero = 0;
}
}
}
else
{
//该位是万亿,亿,万,元位等关键位
if (str3 != "0" && nzero != 0)
{
ch1 = "零" + str1.Substring(temp*1,1);
ch2 = str2.Substring(i,1);
nzero = 0;
}
else
{
if (str3 != "0" && nzero == 0)
{
ch1 = str1.Substring(temp*1,1);
ch2 = str2.Substring(i,1);
nzero = 0;
}
else
{
if (str3 == "0" && nzero >= 3)
{
ch1 = "";
ch2 = "";
nzero = nzero + 1;
}
else
{
if (j >= 11)
{
ch1 = "";
nzero = nzero + 1;
}
else
{
ch1 = "";
ch2 = str2.Substring(i,1);
nzero = nzero + 1;
}
}
}
}
}
if (i == (j-11) || i == (j-3))
{
//如果该位是亿位或元位,则必须写上
ch2 = str2.Substring(i,1);
}
str5 = str5 + ch1 + ch2;
if (i == j-1 && str3 == "0" )
{
//最后一位(分)为0时,加上“整”
str5 = str5 + '整';
}
}
if (num == 0)
{
str5 = "零元整";
}
return str5;
}
{
string str1 = "零壹贰叁肆伍陆柒捌玖"; //0-9所对应的汉字
string str2 = "万仟佰拾亿仟佰拾万仟佰拾元角分"; //数字位所对应的汉字
string str3 = ""; //从原num值中取出的值
string str4 = ""; //数字的字符串形式
string str5 = ""; //人民币大写金额形式
int i; //循环变量
int j; //num的值乘以100的字符串长度
string ch1 = ""; //数字的汉语读法
string ch2 = ""; //数字位的汉字读法
int nzero = 0; //用来计算连续的零值是几个
int temp; //从原num值中取出的值
num = Math.Round(Math.Abs(num),2); //将num取绝对值并四舍五入取2位小数
str4 = ((long)(num*100)).ToString(); //将num乘100并转换成字符串形式
j = str4.Length; //找出最高位
if (j > 15){return "溢出";}
str2 = str2.Substring(15-j); //取出对应位数的str2的值。如:200.55,j为5所以tr2=佰拾元角分
//循环取出每一位需要转换的值
for(i=0;i<j;i++)
{
str3 = str4.Substring(i,1); //取出需转换的某一位的值
temp = Convert.ToInt32(str3); //转换为数字
if (i != (j-3) && i != (j-7) && i != (j-11) && i != (j-15))
{
//当所取位数不为元、万、亿、万亿上的数字时
if (str3 == "0")
{
ch1 = "";
ch2 = "";
nzero = nzero + 1;
}
else
{
if(str3 != "0" && nzero != 0)
{
ch1 = "零" + str1.Substring(temp*1,1);
ch2 = str2.Substring(i,1);
nzero = 0;
}
else
{
ch1 = str1.Substring(temp*1,1);
ch2 = str2.Substring(i,1);
nzero = 0;
}
}
}
else
{
//该位是万亿,亿,万,元位等关键位
if (str3 != "0" && nzero != 0)
{
ch1 = "零" + str1.Substring(temp*1,1);
ch2 = str2.Substring(i,1);
nzero = 0;
}
else
{
if (str3 != "0" && nzero == 0)
{
ch1 = str1.Substring(temp*1,1);
ch2 = str2.Substring(i,1);
nzero = 0;
}
else
{
if (str3 == "0" && nzero >= 3)
{
ch1 = "";
ch2 = "";
nzero = nzero + 1;
}
else
{
if (j >= 11)
{
ch1 = "";
nzero = nzero + 1;
}
else
{
ch1 = "";
ch2 = str2.Substring(i,1);
nzero = nzero + 1;
}
}
}
}
}
if (i == (j-11) || i == (j-3))
{
//如果该位是亿位或元位,则必须写上
ch2 = str2.Substring(i,1);
}
str5 = str5 + ch1 + ch2;
if (i == j-1 && str3 == "0" )
{
//最后一位(分)为0时,加上“整”
str5 = str5 + '整';
}
}
if (num == 0)
{
str5 = "零元整";
}
return str5;
}
展开全部
/// <summary>
///
/// </summary>
/// <param name="money">需要兑换的钱</param>
/// <param name="huiLv">汇率</param>
/// <returns></returns>
public double Format(double money, double huiLv)
{
return money * huiLv;
}
///
/// </summary>
/// <param name="money">需要兑换的钱</param>
/// <param name="huiLv">汇率</param>
/// <returns></returns>
public double Format(double money, double huiLv)
{
return money * huiLv;
}
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询