第五题，求导
1个回答
展开全部
∫∫(3-x-y)dxdy
=∫[0-->1]∫[0-->2] (3-x-y) dydx
=∫[0-->1] (3y-xy-1/2y²) |[0-->2]dx
=∫[0-->1] (6-2x-2) dx
=∫[0-->1] (4-2x) dx
=(4x-x²) [0-->1]
=3
=∫[0-->1]∫[0-->2] (3-x-y) dydx
=∫[0-->1] (3y-xy-1/2y²) |[0-->2]dx
=∫[0-->1] (6-2x-2) dx
=∫[0-->1] (4-2x) dx
=(4x-x²) [0-->1]
=3
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
