Question

一道高一数学题！！！！急求解！！！！！

已知sina-(根号3) * (cosa)=(2m-3)/(2-m)，求m的取值范围？

Answer 1

对楼上作出修改
sina-√3(cosa)
=2[(1/2)sina - (√3/2)cosa]
=2sin(a-π/3)
∴(2m-3)/(2-m)=2sin(a-π/3)∈[-2，2]
即-2≤(2m-3)/(2-m)≤2
∴7/4≤m<2

Answer 2

sina-√3(cosa)
=2[(1/2)sina - (√3/2)cosa]
=2sin(a-π/3)
∴(2m-3)/(2-m)=2sin(a-π/3)∈[-1，1]
即-1≤(2m-3)/(2-m)≤1
∴1≤m≤5/3