
一道高二数学题
1个回答
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a>1 lga>0
0<b<1 lgb<0
k=lgb/lga<0
log(a)b+log(b)a
=lgb/lga+lga/lgb
=k+1/k
=-(-k+1/(-k))
<=-2
0<b<1 lgb<0
k=lgb/lga<0
log(a)b+log(b)a
=lgb/lga+lga/lgb
=k+1/k
=-(-k+1/(-k))
<=-2
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