Question

C#怎么比较三个数的大小并按从大到小的顺序输出？要用if语句。

Answer 1

class Program
{
static void Main(string[] args)
{
int []a=new int[3];
a[0] = 123;
a[1] = 3;
a[2] = 12;
int temp; ;
if (a[0] > a[1])
{
temp = a[1];
a[1] = a[0];
a[0] = temp;
}
if (a[1] > a[2])
{
temp = a[2];
a[2] = a[1];
a[1] = temp;
}
if (a[0] > a[1])
{
temp = a[1];
a[1] = a[0];
a[0] = temp;
}
for (int i = 0; i < 3; i++)
Console.Write(a[i] + " ");
Console.WriteLine("按回车结束");
Console.ReadLine();
}
}

Answer 2

int [] array= new int []{32,12,5} ;
int temp = 0 ;
for (int i = 0 ; i < array.Length - 1 ;i++)
{
for (int j = i + 1 ; j < array.Length-1-i ;j++)
{
if (array[j] > array[j+1])
{
temp = array[j] ;
array[j] = array[j+1] ;
array[j+1] = temp ;
}
}
}

Answer 3

Console.WriteLine("请输入数据,以空格或逗号分开:");
string NumStr=Console.ReadLine();
string[] NumsStr=Numstr.Split(new char[]{' ',','});
string Numstr;
try
{
for(int i=0,i++.i<NumsStr.Length-2)
{
if(double.Parse(NumsStr[i]<=double.Parse(NumsStr[i+1]))
{
Numstr=NumsStr[i+1];
NumsStr[i]=NumsStr[i+1];
NumsStr[i+1]=Numstr;
}
}
foreach(var num in NumsStr)
Console.Write(num+"\t");
}
catch(Exception ex)
{
throw ex;
}