Question

(x+y)(x+y-1)+1/4

Answer 1

是分解因式吗？如果是，应该是这样【(x+y)^2表示x+y 的平方】：
(x+y)(x+y-1)+1/4 （将x+y看作一个整体）
=(x+y)^2 -(x+y)+1/4 (这刚好是一个完全平方差公式)
=(x+y-1/2)^2
希望对你有帮助！

Answer 2

是分解因式吗？
(x+y)(x+y-1)+1/4
=(x+y）²-（x+y）+1/4
=(x+y-1/2)²

Answer 3

(x+y)(x+y-1)+1/4
=(x+y)²-(x+y)+1/4
=(x+y-1/2)²

Answer 4

(x+y)(x+y-1)+1/4
=(x+y)²-(x+y)+1/4
=(x+y-1/2)²

Answer 5

将x＋y看做一个整体。设为T这样。