Question

已知m，x，y满足条件：（1）2/3（x-5）的2次方+5|m|=0

已知m,x,y满足条件：（1）2/3(x-5)2+5×(m的绝对值）=0；（2）-2a2b^(y+1)与3b3a2是同类项。求代数式0.75x2y+5m2x-{-7/16x2y+[1/4xy2+(-3/16x2y-3.475xy2)]-6.27xy2}的值。请大家帮帮忙，要快，谢了

Answer 1

说实话 你的等式给得我都看得不怎么懂 只能蒙着来了
根据（1）可知x=5 m=0
（2）可知y=2所以等式的结果是7.85

Answer 2

①2/3(x-5)²+5│m│=0 则 x=5 m=0
②-2a²b的y+1次方与3a²b³是同类项，则 y+1=3 y=2
-{-7/16x²y+[-1/4xy²+(-3/16x²y-3.475xy²)]-6.275xy²}+0.375x²y+5m²x
=-{-7/16x²y+[-1/4xy²-3/16x²y-3.475xy²]-6.275xy²}+0.375x²y m=0
=-{-7/16x²y-1/4xy²-3/16x²y-3.475xy²-6.275xy²}+0.375x²y
=-{-10/16x²y-10xy²}+0.375x²y
=0.625x²y+10xy²+0.375x²y
=x^2y+10xy^2
=50+200
=250