Question

matlab GUI 中，if -----text1的'visible'属性是'on----属性条件语句的编写

matlab GUI 中，pushbutton1中set(handles.text1,'visible','on');在pushbutton2中如何编写函数：if -----text1的'visible'属性是'on'-----，pushbutton2 call back就设置set(handles.text2,'visible','on').。。。。即按下一个按钮显示一个文本，再按下第二个按钮根据条件有选择的显示另一个文本。谢谢~

Answer 1

function pushbutton1_Callback(hObject, eventdata, handles)
h1=findobj(handles.text1,'visible','off')%获取按键1的可视化句柄
set(h1,'visible','on')%设置句柄为可见
% hObject handle to pushbutton1 (see GCBO)
% eventdata reserved - to be defined in a future version of MATLAB
% handles structure with handles and user data (see GUIDATA)

% --- Executes on button press in pushbutton2.
function pushbutton2_Callback(hObject, eventdata, handles)
h2=findobj(handles.text1,'visible','on')%再次获得按键1句柄
m1=findobj(handles.text2,'visible','off')%获得按键2的句柄
%m2=findobj(handles.text2,'visible','on')
if h2==findobj(handles.text1,'visible','on')%判断句柄值是否为可视
set(m1,'visible','on')%如果是，将按键2句柄值改为可视
else%如果不是，添加语句
end
%前提是两个text的’visible‘为off我已经试过了，你试试