Question

初一数学：如图,求∠A+∠B+∠D+∠F+∠P+∠Q的度数

http://hi.baidu.com/gcy123789/album/item/9492408bae3044c2a5c27224.html# 里面有图，急！！

Answer 1

总和是360°
你用“三角形外角等于不相邻的两个内角之和”，
A+B＝AEC，D+F＝DEC，P+Q=FOQ，
FOQ=OCE+OEC，
所以A+B+D+F+P+Q=AEC+DEC+OCE+OEC=180°+180°=360°

Answer 2

∠A+∠B+∠D+∠F+∠P+∠Q
=(∠A+∠B)+(∠D+∠F)+(∠P+∠Q)
=(360-∠ACB)+(360-∠DEF)+(360-∠POQ)
=360*3-(∠ACB+∠DEF+∠POQ)
=360*3-(∠ECO+∠CEO+∠COE)
=360*3-360
=720度

Answer 3

∠A+∠B+∠D+∠F+∠P+∠Q=3X180-180=360

∠A+∠B=180-∠FCD
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