已知{4a-3b=6c,a+2b=7c.求代数式2a+3b+6c/a+5b+7c的值
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2011-04-04 · 知道合伙人教育行家
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4a-3b=6c......(1)
a+2b=7c......(2)
(1)÷(2)得:
(4a-3b)/(a+2b) = 6/7
28a-21b=6a+12b
22a=33b
2a=3b
将6c=4a-3b,7c=a+2b,2a=3b代入原式得:
(2a+3b+6c)/(a+5b+7c)
= (2a+3b+(4a-3b))/(a+5b+(a+2b))
= (6a)/(2a+7b)
=(3*2a)/(3b+7b)
=3*3b/(10b)
=9/10
a+2b=7c......(2)
(1)÷(2)得:
(4a-3b)/(a+2b) = 6/7
28a-21b=6a+12b
22a=33b
2a=3b
将6c=4a-3b,7c=a+2b,2a=3b代入原式得:
(2a+3b+6c)/(a+5b+7c)
= (2a+3b+(4a-3b))/(a+5b+(a+2b))
= (6a)/(2a+7b)
=(3*2a)/(3b+7b)
=3*3b/(10b)
=9/10
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