Question

数学七年级下册

(5m³n²－6m²)÷(3m)=
(6a²b-5a²c²)÷(－3a²)=
(16x⁴+4x²+x)÷x=
(3a²b－2ab+2ab²)÷(ab)=
(－4a³+6a²b³+3a³b³)÷(－4a²)=
(2/5mn³－m²n²+1/6n⁴)÷(2/3n²)=
(1/10xy²+1/4y²－1/2y)÷(1/5y)=
[(x+1)(x+2)-2]÷x=
要过程

Answer 1

(5m³n²－6m²)÷(3m)=m²（5mn²－6)÷(3m)=m²（5mn²－6)x1/(3m)=5/3m²-2m
(6a²b-5a²c²)÷(－3a²)=a²（6b-5c²）x（-1/3a²）=（6b-5c²）x（-1/3）=5/3c²-2b
(16x⁴+4x²+x)÷x=16x³+4x+1
(3a²b－2ab+2ab²)÷(ab)=(3a²b－2ab+2ab²)1/(ab)=3a-2+2b
(－4a³+6a²b³+3a³b³)÷(－4a²)=(－4a³+6a²b³+3a³b³)1/(－4a²)=
a-3b³/2-3ab³/4
(2/5mn³－m²n²+1/6n⁴)÷(2/3n²)=(2/5mn³－m²n²+1/6n⁴)(3n²/2）=3/5mn
-m²3/2+1/4n²
(1/10xy²+1/4y²－1/2y)÷(1/5y)=(1/10xy²+1/4y²－1/2y)x5y=1/2xy+5/4y-5/2y
[(x+1)(x+2)-2]÷x= (x²+3x+2-2)*1/x=x+3