Question

分解因式 有过程加20分悬赏

16a^2-8ab+b^2
4（x+y)^2-12(x+y)+9
x^2+2x(y-z)+(z-y)^2

Answer 1

16a^2-8ab+b^2=(4a)²-2×4ab+b²=(4a+b)²
4（x+y)^2-12(x+y)+9=(2x+2y)²-2×(2x+2y)×3+3²=(2x+2y-3)²
x^2+2x(y-z)+(z-y)^2=x^2+2x(y-z)+(y-z)^2=(x+y-z)²

Answer 2

16a^2-8ab+b^2
=（4a）^2-2*4a*b+b^2
=(4a-b)^2

4（x+y)^2-12(x+y)+9
=[2[x+y]]^2-2*2(x+y)*3+3^2
=[2(x+y)+3]^2

x^2+2x(y-z)+(z-y)^2
=x^2-2x*(z-y)+(z-y)^2
=[x-(z-y)]^2