Question

x-3分之2-x+3-x分之1=1 怎么解分式方程

Answer 1

(2-x)/(x-3) + 1/(3-x）= 1
移项：(2-x)/(x-3) + 1/(3-x）- 1 = 0
统分：(2-x)/(x-3) - 1/(x-3）- (x-3)/(x-3) = 0
{ (2-x) - 1 - (x-3) } /(x-3) = 0
{ -2x +4 } /(x-3) = 0
-2x +4=0
x=2

Answer 2

先通分相加，即(2—x—1）/(x—3)＝1，于是有1—x＝x—3，得出x＝2

Answer 3

(2-x)/(x-3)-1/(x-3)=1
（4-2x）/(x-3)=0
因为x-3是分母，所以不为0
4-2x=0
x=2

Answer 4

你这个方程应该写错了，有X-X项？正常的话，方程两边成X，解一元二次方程。

Answer 5

(2-x)/(x-3)+1/(3-x)=1
(2-x)/(x-3)-1/(x-3)=1
(2-x-1)/(x-3)=1
(1-x)(x-3)=1
1-x=x-3
2x=4
x=2