化简：(x方-4x+4分之x方-4)+ x+2分之2-x)除以x-2分之x. 详细过程，谢谢.
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解答：
[(x^2-4)/(x^2-4x+4)+(2-x）/(x+2)]÷x/(x-2)
=[(x+2)(x-2)/(x-2)^2-(x-2)/(x+2)]*(x-2)/x
=[(x+2)/(x-2)-(x-2)/(x+2)]*(x-2)/x
=[(x+2)^2-(x-2)^2]/[(x-2)(x+2)*(x-2)/x
=8x/[(x-2)(x+2)]*(x-2)/x
=8/(x+2)
[(x^2-4)/(x^2-4x+4)+(2-x）/(x+2)]÷x/(x-2)
=[(x+2)(x-2)/(x-2)^2-(x-2)/(x+2)]*(x-2)/x
=[(x+2)/(x-2)-(x-2)/(x+2)]*(x-2)/x
=[(x+2)^2-(x-2)^2]/[(x-2)(x+2)*(x-2)/x
=8x/[(x-2)(x+2)]*(x-2)/x
=8/(x+2)
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