Question

解分式方程(5x-4)/(x-2)=(4x+10)/(3x-6)-1

Answer 1

(5x-4)/(x-2)=(4x+10)/3(x-2)-1
两边乘3(x-2)
3(5x-4)=4x+10-3(x-2)
15x-12=4x+10-3x+6
15x-12=x+16
14x=28
x=2
经检验，x=2时分母x-2=0，是增根，舍去
所以方程无解

Answer 2

(5x-4)/(x-2)=(4x+10)/(3x-6)-1
(5x-4)/(x-2)=(4x+10)/3(x-2)-1 两边同时乘3(x-2)
3（5x-4)=4x+10-3(x-2)
15x-12-4x+3x-10-6=0
14x=28
x=2

因为分母不能为0，x-2不等于0，x不等于2

无解

Answer 3

(5x-4)/(x-2)=(4x+10)/3(x-2)-1
两边乘3(x-2)
3(5x-4)=4x+10-3(x-2)
15x-12=4x+10-3x+6
15x-12=x+16
14x=28
x=2
检验，当x=2时，分母3（x-2）=0
所以原方程无解

Answer 4

此方程无解