Question

分解法因式计算： 1.x五次方-8x²-x³+8 2.x四次方-4x²y²+4y四次方-3x²+6y²-

4.(x-1)(x-2)(x+3)(x+6)-5x²
5.(x-3)²9(x-1)
1.x五次方-8x²-x³+8
2.x四次方-4x²y²+4y四次方-3x²+6y²-4
3.x四次方-4x²y²-3x²+6y²-4

Answer 1

1、x^5-8x²-x³+8
=x²(x³-8)-(x³-8)
=(x²-1)(x³-8)
=(x+1)(x-1)(x-2)(x²+8x+64)
2、x^4-4x²y²+4y^4-3x²+6y²-4
=(x²-2y²)²-3(x²-2y²)-4
将(x²-2y²)看做一个整体t，即t²-3t-4=(t-4)(t+1)
∴原式=(x²-2y²-4)(x²-2y²+1)
3、x^4-4x²y²-3x²+6y²-4，抱歉，不会= =、
4、(x-1)(x-2)(x+3)(x+6)-5x²
=(x-1)(x+6)(x-2)(x+3)-5x²
=(x²-6+5x)(x²-6+x)-5x²
=(x²-6)²+6x(x²-6)+5x²-5x²
=(x²-6)(x²+6x-6)
5、9(x-3)²(x-1)，似乎不需要再分解了

Answer 2

答案为
1.(x-2)(x-1)(x+1)(x²+2x+4)
2.(x²-2y²-4)(x²-2y²+1)
3.??????
4.(x²-6)(x²+6x-6)
5.!!!!!!

Answer 3

X五次方-X三次方-8X平方+8
=X三次方(X平方-1)-8(X平方-1)
=(X平方-1)(X三次方-8)
=(X+1)(X-1)(X-2)(X平方+2X+4)

Answer 4

³