Question

编程计算X的n次方。要求：用递归函数，用TC编译

Answer 1

#include <stdio.h>
double pow(double x,int n)
{
if(n==1)
{
return x;
}
else
{
double temp=pow(x,n-1);
return (x*temp);
}
}
void main()
{
double a;
int b;
printf("Please input two numbers:");
scanf("%lf%d",&a,&b);
printf("%lf^%d=%lf\n",a,b,pow(a,b));
} 这个代码是对的。

Answer 2

#include <stdio.h>
double pow(double x,int n)
{
if(1==n)
{
return x;
}
else
{
double temp=pow(x,n-1);
return (x*temp);
}
}
void main()
{
double a;
int b;
printf("Please input two numbers:");
scanf("%lf%d",&a,&b);
printf("%lf^%d=%lf\n",a,b,pow(a,b));
}

Answer 3

long f(x,n)
{ if(n==1)
f(x,n)=x;
else if(n==0)
f(x,n)=1;
else
f(x,n)=f(x,n-1)*x:
}
void main()
{ int x,n;
long b;
scanf("%d %d",&x,&n);
b=f(x,n);
printf("%ld",b);
}