Question

求c#代码 弹出网页消息框并跳转到某个网页，用一个函数实现 AlertAndRedirect（"弹出的消息","要跳转到的"

Answer 1

public static void AlertAndRedirect(string messageString, string redirectPage)
{
Page currentPage = HttpContext.Current.Handler as Page;
string __Jscript = @"<script>";
__Jscript += @"alert('" + messageString + "');";
__Jscript += @"window.location.href='" + redirectPage + "';</script>";
currentPage.ClientScript.RegisterStartupScript(typeof(System.String), redirectPage.GetHashCode().ToString(), __Jscript);
}

Answer 2

楼上的方法不错。
给你个更简单的。

Response.Write("<script>alert('提示消息');location.replace('a.aspx');</script>;");