Question

因式分解求助！

a³+5a²b-300ab²
5（x²-2x）²-14（x²-2x）-3
(x+3)(x+2)(x+8)(x-3)-64
a²+ab-2b²+b-a

急求!能做几道做几道!

Answer 1

a³+5a²b-300ab²
=a(a^2+5ab-300b^2)
=a(a-15b)(a+20b)

5(x²-2x)²-14(x²-2x)-3
=(5x^2-10x+1)(x^2-2x-3)
=(x-3)(x+1)(5x^2-10x+1)

(x+3)(x+2)(x+8)(x-3)-64
=(x^2+5x+6)(x^2+5x-24)-64
=(x^2+5x)^2-18(x^2+5x)-208
=(x^2+5x-26)(x^2+5x+8)

a²+ab-2b²+b-a
=(a-b)(a+2b)-(a-b)
=(a-b)(a+2b+1)

Answer 2

a³ + 5a²b - 300ab² = a (a + 20b) (a - 15b)
5(x²-2x)² - 14(x²-2x) - 3 = (x-3)(x+1)(5x²-10x+1)
(x+3)(x+2)(x+8)(x-3) - 64 = (x²+5x-26) (x²+5x+8)
a² + ab - 2b² + b - a = (a+2b-1) (a-b)

Answer 3

a(a+15b)(a-20b);
(5x^2-10x+1)(x-3)(x+1);
(x²+5x-26) (x²+5x+8)
(a-b)(a+2b-1)