求直线 2x-3y+1=0 关于直线3x-2y+5=0对称的直线方程

求直线2x-3y+1=0关于直线3x-2y+5=0对称的直线方程谢谢... 求直线 2x-3y+1=0 关于直线3x-2y+5=0对称的直线方程
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塞漫O
2011-04-14
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由 2x-3y+1=0和3x-2y+5=0得它们的交点为(-13/5,-7/5)
设所求的对称直线方程为y-(-7/5)=k[x-(-13/5)]
因为两条直线与对称直线的夹角相等
所以 | (3/2-2/3)/[1+(3/2)*(2/3)] |=| (3/2-k)/(1+3/2*k) |

即k=2/3
所以所求直线方程为y+(7/5)=(2/3)*(x+13/5)
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解;直线2x-3y=-1与x 轴交点为(-1/2.0)
直线2x-3y=-1与3x-2y=-5的交点为(-13/5,-7/5)
直线y=kx+b上与(-1/2,0)对称的点为(-5/3,7/6)
把(-13/5,-7/5) 和(-5/3,7/6)代入y=kx+b中
得k=11/4 b=23/4
直线 y=11x/4+23/4
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2011-04-15
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敏捷且实诚的小鸥3690
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这个应该有很多的算法吧。
给出我的算法,
1.求出交点A。
2.在2x-3y+1=0随便找一点,并计算出关于3x-2y+5=0对称的点B。
3.直线AB即为所求。
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