Question

.net 远程获取的字符串XML怎么解析？ 如 string xmlResponseStr = PostXMLRequest(xmlString);

要源码、

Answer 1

可以把我以前做的解析和生成XML的代码给你看一下，你可以参考参考：

代码如下：
public static class PaperXMLManager
{

/// <summary>
/// 输入试卷信息 生成 试卷内容xml字符串
/// </summary>
public static void GetExamPaperXMLStr(XmlDocument objXmlDoc, EntityArrayList<Item> items, string paperCode, ExamPolicy examPolicy)
{
XmlNode root = objXmlDoc.SelectSingleNode("ExamPaper");
XmlNode node;
XmlElement subnode;
if (root == null)
{
root = objXmlDoc.CreateElement("ExamPaper"); //创建一个<ExamPaper>根节点
objXmlDoc.AppendChild(root);
}
else
{
root = objXmlDoc.SelectSingleNode("ExamPaper");//查找<ExamPaper>根节点
}

foreach (Item it in items)
{
node = objXmlDoc.CreateElement("Item");

subnode = objXmlDoc.CreateElement("Code");
subnode.InnerText = it.Code;
node.AppendChild(subnode);
subnode = objXmlDoc.CreateElement("Ver");
subnode.InnerText = it.Ver.ToString();
node.AppendChild(subnode);
subnode = objXmlDoc.CreateElement("Score");
subnode.InnerText = examPolicy.ScorePerItem.ToString();
node.AppendChild(subnode);
subnode = objXmlDoc.CreateElement("EPCode");
subnode.InnerText = examPolicy.EPCode;
node.AppendChild(subnode);

root.AppendChild(node);
}
}

/// <summary>
/// 获取Xml格式字符串的内容
/// </summary>
/// <param name="str">Xml格式字符串</param>
/// <returns>Xml内容的DataTable</returns>
public static DataTable GetItemTable(string str)
{
XmlDocument objXmlDoc = GetXmlDocByStr(str);
DataTable dt = new DataTable();
dt.Columns.Add("Code");
dt.Columns.Add("Ver");
dt.Columns.Add("Score");
dt.Columns.Add("EPCode");
XmlNodeList nodes = objXmlDoc.GetElementsByTagName("Item");
foreach (XmlNode xmlNode in nodes)
{
DataRow dr = dt.NewRow();
for (int j = 0; j < xmlNode.ChildNodes.Count; j++)
{
dr[j] = xmlNode.ChildNodes[j].InnerText;
}
dt.Rows.Add(dr);
}
return dt;
}

/// <summary>
/// 获取Xml的内容
/// </summary>
/// <param name="objXmlDoc">Xml文件</param>
/// <returns>Xml内容的DataTable</returns>
public static DataTable GetItemTable(XmlDocument objXmlDoc)
{
DataSet ds = new DataSet();
StringReader read = new StringReader(objXmlDoc.SelectSingleNode("ExamPaper").OuterXml);
ds.ReadXml(read);
DataTable tblRes = new DataTable();
tblRes = ds.Tables[0];
return tblRes;
}

/// <summary>
/// 从指定格式的字符串中加载Xml文档
/// </summary>
/// <param name="str">xml格式的字符串</param>
/// <returns>xml文档对象</returns>
public static XmlDocument GetXmlDocByStr(string str)
{
XmlDocument dom = new XmlDocument();
dom.LoadXml(str);
return dom;
}

/// <summary>
/// 在当前XML中找到指定值的节点
/// </summary>
/// <param name="objXmlDoc">xml</param>
/// <param name="itemCode">节点内容</param>
/// <returns>节点</returns>
public static XmlNode GetNode(XmlDocument objXmlDoc, string itemCode)
{
XmlNode Nodelist = objXmlDoc.SelectSingleNode("ExamPaper");

foreach (XmlNode node in Nodelist.SelectNodes("Item"))
{
if (node.SelectSingleNode("Code").InnerText == itemCode)
{
return node;
}
}
return null;
}

/// <summary>
/// 替换掉XML文件中值为oldItemCode的节点下子节点的值
/// </summary>
/// <param name="objXmlDoc">xml对象</param>
/// <param name="oldItemCode">指定节点的值</param>
/// <param name="code">试题编码</param>
/// <param name="ver">试题版本</param>
/// <param name="score">试题分值</param>
/// <param name="epcode">策略编号</param>
/// <returns>替换后的XML对象</returns>
public static XmlDocument ReplaceItem(XmlDocument objXmlDoc, string oldItemCode, string code, string ver, string score, string epcode)
{
try
{
XmlNode node = GetNode(objXmlDoc, oldItemCode);
node.SelectSingleNode("Code").InnerText = code;
node.SelectSingleNode("Ver").InnerText = ver;
node.SelectSingleNode("Score").InnerText = score;
node.SelectSingleNode("EPCode").InnerText = epcode;
return objXmlDoc;
}
catch
{
return objXmlDoc;
}
}

/// <summary>
/// 删除选定节点
/// </summary>
/// <param name="nodeText">节点内容</param>
/// <param name="xmlStr">xml字符串</param>
/// <returns>删除后XmlDocument对象</returns>
public static XmlDocument DelNode(string nodeText, string xmlStr)
{
XmlDocument xmlDoc = GetXmlDocByStr(xmlStr);
XmlNode node = GetNode(xmlDoc, nodeText);
if (xmlDoc != null)
{
XmlNode Nodelist = xmlDoc.SelectSingleNode("ExamPaper");
Nodelist.RemoveChild(node);
return xmlDoc;
}
return xmlDoc;
}
}

以上的方法多一些~你也可以参考我下面的代码~知道XML节点格式后直接解析为一个DataTable，这样你知道内容了就可以显示了：

代码如下：
/// <summary>
/// 从指定格式的字符串中加载Xml文档
/// </summary>
/// <param name="str">xml格式的字符串</param>
/// <returns>xml文档对象</returns>
public static XmlDocument GetXmlDocByStr(string str)
{
XmlDocument dom = new XmlDocument();
dom.LoadXml(str);
return dom;
}

/// <summary>
/// 获取Xml的内容
/// </summary>
/// <param name="objXmlDoc">Xml文件</param>
/// <returns>Xml内容的DataTable</returns>
public static DataTable GetItemTable(string str)
{
XmlDocument objXmlDoc = GetXmlDocByStr(str);
DataTable dt = new DataTable();
dt.Columns.Add("Code");
dt.Columns.Add("EpCode");
dt.Columns.Add("Ver");
dt.Columns.Add("Score");
dt.Columns.Add("UserScore");
dt.Columns.Add("RightAnswer");
dt.Columns.Add("UserAnswer");
XmlNodeList nodes = objXmlDoc.GetElementsByTagName("Item");
foreach (XmlNode xmlNode in nodes)
{
DataRow dr = dt.NewRow();
for (int j = 0; j < xmlNode.ChildNodes.Count; j++)
{
dr[j] = xmlNode.ChildNodes[j].InnerText;
}
dt.Rows.Add(dr);
}
return dt;
}
}

Answer 2

你需要怎么解析？填充到实体类？序列化是最好的选择

追问

不是、 是想直接把远程调的数据显示在页面、 谢谢