Question

java编程：类A能计算2个正整数的最大公约数，类B能计算2个正整数的最小公倍数， 求错误，不会改，谢谢！

//类B中有一个成员变量是用类A的声明对象

class A //计算2个正整数的最大公约数
{
int max=0;
public int big(int x,int y)
{
if(x=y)
{
max=x;//如果2个数相等，则最大公约数为他们本身
}
else if(x<y) //如果2个数不相等，则用2个数依次除以从1开始一直到2个数中较小的那个数来判断他们的最大公约数
{
for(int i=1;i<=x;i++)
{
if(x%i==0&&y%i==0)
{
max=i;
}
}
}
else
{
for(int i=1;i<=y;i++)
{
if(y%i==0&&x%i==0)
{
max=i;
}
}
}
return max;
}
}
class B //计算2个正整数的最小公倍数
{
int min=0;
public int small(int x,int y)
{
if(x=y)
{
min=x;//如果2个数相等，则最小公倍数为他们本身
}
else if(x<y)//如果2个数不相等，则从较大的那个数开始一直到这2个数的乘积除以这2个数，直到出现能同时整除这2个数的数，结束循环
{
for(int i=y;i<=x*y;i++)
{
if(i%y==0&&i%x==0)
{
min=i;
}
break;
}
}
else
{
for(int i=x;i<=x*y;i++)
{
if(i%x==0&&i%y==0)
{
min=i;
}
break;
}
}
return min;
}
}
public class P78_4
{
public static void main(String args[])
{
A a=new A();
System.out.println("最大公约数为："+a.big(6,9));
B b=new B();
System.out.println("最小公倍数为："+b.small(6,9));
}
}

Answer 1

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6. Timer integrated

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Does not affect the playback performance in the premise of maintaining low power mode to CPU

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5. Low Power Audio

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Answer 2

你把等于号和赋值好弄乱了，if(x=y)这里出错，这是赋值，不是比较，改成x==y试试看

Answer 3

t java.util.*;

class Main
{
public static int gcd(int m,int n) {
while (true) {
if ((m = m % n) == 0) return n;
if ((n = n % m) == 0) return m;
}
}
public static void main(String args[]) throws Exception
{
Scanner cin=new Scanner(System.in);
int a=cin.nextInt(),b=cin.nextInt();
int c = gcd(a,b);
System.out.println("最小公倍数：" + a * b / c + "\n最大公约数：" + c);
}
}
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