Question

数学题因式分解!过程!

（a²+b²）²-4a²b²

Answer 1

（a²+b²）²-4a²b²
=(a²+b²+2ab)(a²+b²-2ab)
=(a+b)²(a-b)²

Answer 2

=a^4+2a²b²+b^4-4a²b²=a^4-2a²b²+b^4=(a²-b²)²

Answer 3

（a²+b²）²-4a²b²
=(a²+b²+2ab)(a²+b²-2ab)
=(a+b)²(a-b)²
=（根号a+根号b )（根号a-根号b)(a+b)²

Answer 4

a^4+2a^²b^²+b^4-4a^2b^2=a^4-2a^2b^2+b^4=(a^2-b^2)^2

Answer 5

(a^2+b^2)^2-4a^2b^2 =a^4+b^4-2a^2b^2 =(a^2-b^2)^2 =( a^2+b^2)(a^2-b^2) 格式有点乱，请见谅！！!

Answer 6

（a²+b²）²-4a²b²
=(a²+b²+2ab)(a²+b²-2ab)
=(a+b)²(a-b)²