Question

在PHP中如何规定文章在网页中显示的长度？？？求例子！！！

PHP 调用数据库里的文章 在规定大小的范围内显示 但是文章太长 后面的无法显示 需要用 “...” 结尾。

Answer 1

是规定字节长度吗？
可以这样写：
$content = '文章'; //文章
$start = 0; //从0开始
$max = 200; //最大限制200个汉字
$com = 'utf-8'; //字符编码
echo mb_substr($content,$start,$max,$com);

Answer 2

//获取字符串
function getstr($string, $length, $bm='utf-8') {

$string = trim($string);

if($length && strlen($string) > $length) {
//截断字符
$wordscut = '';
if(strtolower($bm) == 'utf-8') {
//utf8编码
$n = 0;
$tn = 0;
$noc = 0;
while ($n < strlen($string)) {
$t = ord($string[$n]);
if($t == 9 || $t == 10 || (32 <= $t && $t <= 126)) {
$tn = 1;
$n++;
$noc++;
} elseif(194 <= $t && $t <= 223) {
$tn = 2;
$n += 2;
$noc += 2;
} elseif(224 <= $t && $t < 239) {
$tn = 3;
$n += 3;
$noc += 2;
} elseif(240 <= $t && $t <= 247) {
$tn = 4;
$n += 4;
$noc += 2;
} elseif(248 <= $t && $t <= 251) {
$tn = 5;
$n += 5;
$noc += 2;
} elseif($t == 252 || $t == 253) {
$tn = 6;
$n += 6;
$noc += 2;
} else {
$n++;
}
if ($noc >= $length) {
break;
}
}
if ($noc > $length) {
$n -= $tn;
}
$wordscut = substr($string, 0, $n);
} else {
for($i = 0; $i < $length - 1; $i++) {
if(ord($string[$i]) > 127) {
$wordscut .= $string[$i].$string[$i + 1];
$i++;
} else {
$wordscut .= $string[$i];
}
}
}
$string = $wordscut;
}
return trim($string);
}