Question

跪求各位大大解决下MATLAB优化中的燃眉之急 ??? Attempt to execute SCRIPT fmincon as a function:

??? Attempt to execute SCRIPT fmincon as a function:
F:\毕业设计\设计正文\fmincon.m

Error in ==> fmincon at 6
[x,fval,exitflag,output] = fmincon('exefun',x0,[],[],[],[],lb,ub,'execonfun',options);
原程序是
function f = exefun(x)
f = x(0)*42;

function [c,ceq] = execonfun(x)
c=[ 1-(35-2.5)*x(0)/(28+8+4*x(0));
2.5*189*(1.718*63.69/(10*x(0)*35*x(0)))^(1/2)/750-1;
1.718*63.69*2.45*1.65/(10*x(0)*600)-1;];
ceq = [];

x0=(2);
lb=(1.75);
ub=(6);
options = optimset('LargeScale','off');
[x,fval,exitflag,output] = fmincon('exefun',x0,[],[],[],[],lb,ub,'execonfun',options);

Answer 1

function f = exefun(x)
f = x(1)*42;%%x的索引数是从1开始的
%%%%%%%%%%%%%%%%%
function [c,ceq] = execonfun(x)
c=[ 1-(35-2.5)*x(1)/(28+8+4*x(1));
2.5*189*(1.718*63.69/(10*x(1)*35*x(1)))^(1/2)/750-1;
1.718*63.69*2.45*1.65/(10*x(1)*600)-1;];
ceq = []; %%下面一样，x(0)改为x(1)
%%%%%%%%%%%%%%%%%%%%%%%%%%
>> x0=[2];%%x0是初值，你的代码只有一个变量，所以x0就一个值,中括号
lb=1.75;
ub=6;%%不用加括号
options = optimset('LargeScale','off');
[x,fval,exitflag,output] = fmincon('exefun',x0,[],[],[],[],lb,ub,'execonfun',options);
Optimization terminated: first-order optimality measure less
than options.TolFun and maximum constraint violation is less
than options.TolCon.
Active inequalities (to within options.TolCon = 1e-006):
lower upper ineqlin ineqnonlin
1

追问

先谢谢你的回答 呵呵 请问后面这些是程序上面的还是说明 全部写入么
Optimization terminated: first-order optimality measure less 。。。
我全部输入后的结果是
??? Attempt to execute SCRIPT fmincon as a function:
F:\毕业设计\设计正文\fmincon.m
Error in ==> fmincon at 5
[x,fval,exitflag,output] = fmincon('exefun',x0,[],[],[],[],lb,ub,'execonfun',options);