一道数学题~!急~!追分~!
若A=10061006/10071007B=10071007/10081008C=10081008/10091009,问A,B,C谁最大...
若A=10061006/10071007
B=10071007/10081008
C=10081008/10091009,
问A,B,C谁最大 展开
B=10071007/10081008
C=10081008/10091009,
问A,B,C谁最大 展开
4个回答
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B/A=(10071007/10081008)/(10061006/10071007)
=(10071007)^2/(10061006*10081008)
=(10071007)^2/[(1006*1008)*(1001)^2]
=(10071007)^2/[(1007-1)*(1007+1)*(1001)^2]
=(10071007)^2/[(1007^2-1)*(1001)^2]
=(10071007)^2/[(10071007^2-(1001)^2]>1
B>A
C/B=(10081008/10091009)/(10071007/10081008)
=(10081008)^2/(10071007*10091009)
=(10081008)^2/[(1007*1009)*(1001)^2]
=(10081008)^2/[(1008-1)*(1008+1)*(1001)^2]
=(10081008)^2/[(1008^2-1)*(1001)^2]
=(10081008)^2/[(10081008^2-(1001)^2]>1
C>B
C最大
=(10071007)^2/(10061006*10081008)
=(10071007)^2/[(1006*1008)*(1001)^2]
=(10071007)^2/[(1007-1)*(1007+1)*(1001)^2]
=(10071007)^2/[(1007^2-1)*(1001)^2]
=(10071007)^2/[(10071007^2-(1001)^2]>1
B>A
C/B=(10081008/10091009)/(10071007/10081008)
=(10081008)^2/(10071007*10091009)
=(10081008)^2/[(1007*1009)*(1001)^2]
=(10081008)^2/[(1008-1)*(1008+1)*(1001)^2]
=(10081008)^2/[(1008^2-1)*(1001)^2]
=(10081008)^2/[(10081008^2-(1001)^2]>1
C>B
C最大
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