Question

急求！！ 因式分解： x ² - y²+ax+ay

Answer 1

这题分两步看,前面x ² - y² 是特殊的完全平方可化为(x+y)(x-y),后面的ax+ay有公因子a,化为a(x+y)
所以分解为:
x ² - y²+ax+ay=(x ² - y²)+(ax+ay)
=(x+y)(x-y)+a(x+y) 做到此步可看出又有因式(x+y),可进一步得到
=(x+y)(x-y+a)

Answer 2

x^2- y^2+ax+ay
=(x+y)(x-y)+a(x+y)
=(x+y)(x-y+a)

Answer 3

=(x+y)(x-y)+a(x+y)
=(x+y)(x-y+a)

Answer 4

（x-y) (x+y) + a(x+y)
= (x-y+a)(x+y)

Answer 5

x^2- y^2+ax+ay
=(x+y)(x-y)+a(x+y)
=(x+y)(x-y+a)
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