Question

关于你那个如何修改sql server 2000中，表的创建时间

QQ:125819398希望指导下

Answer 1

SELECT TOP 100 PERCENT --a.id,
CASE WHEN a.colorder = 1 THEN d.name ELSE '' END AS 表名,
CASE WHEN a.colorder = 1 THEN isnull(f.value, '') ELSE '' END AS 表说明,
a.colorder AS 字段序号, a.name AS 字段名, CASE WHEN COLUMNPROPERTY(a.id,
a.name, 'IsIdentity') = 1 THEN '√' ELSE '' END AS 标识,
CASE WHEN EXISTS
(SELECT 1
FROM dbo.sysindexes si INNER JOIN
dbo.sysindexkeys sik ON si.id = sik.id AND si.indid = sik.indid INNER JOIN
dbo.syscolumns sc ON sc.id = sik.id AND sc.colid = sik.colid INNER JOIN
dbo.sysobjects so ON so.name = si.name AND so.xtype = 'PK'
WHERE sc.id = a.id AND sc.colid = a.colid) THEN '√' ELSE '' END AS 主键,
b.name AS 类型, a.length AS 长度, COLUMNPROPERTY(a.id, a.name, 'PRECISION')
AS 精度, ISNULL(COLUMNPROPERTY(a.id, a.name, 'Scale'), 0) AS 小数位数,
CASE WHEN a.isnullable = 1 THEN '√' ELSE '' END AS 允许空, ISNULL(e.text, '')
AS 默认值, ISNULL(g.[value], '') AS 字段说明, d.crdate AS 创建时间,
CASE WHEN a.colorder = 1 THEN d.refdate ELSE NULL END AS 更改时间
FROM dbo.syscolumns a LEFT OUTER JOIN
dbo.systypes b ON a.xtype = b.xusertype INNER JOIN
dbo.sysobjects d ON a.id = d.id AND d.xtype = 'U' AND
d.status >= 0 LEFT OUTER JOIN
dbo.syscomments e ON a.cdefault = e.id LEFT OUTER JOIN
dbo.sysproperties g ON a.id = g.id AND a.colid = g.smallid AND
g.name = 'MS_Description' LEFT OUTER JOIN
dbo.sysproperties f ON d.id = f.
id AND f.smallid = 0 AND
f.name = 'MS_Description'
ORDER BY d.name, a.colorder

你运行一下这个语句，会非常好的列出数据库中所有表的数据字典，创建时间等等信息。

追问

恩 那我想更新怎么办？

追答

更新表创建时间是没办法用SQL语句来修改的，因为SYSOBJECTS里面的数据不允许执行UPDATE。
我看到过以前有遇到这样问题的，他们的方法是将表导出去，然后再导进来，时间就变了。

追问

把你的QQ留下来好了 我们具体交流 我的是125819398你的QQ也留一下不然我不知道是哪位

追答

--------------在自己的数据库上运行以下语句-------------------
sp_configure 'allow updates',1 reconfigure with override
update sysobjects set crdate='2011-01-01' where name='表名大写'
sp_dboption '数据库名','dbo use only','false'
sp_configure 'allow updates',0
reconfigure with override

Answer 2

表述的问题太不明确了,若把以前建立的表搞成现在的日期的话,设计表修改除主键外的任何字段名称存盘后,再次设计表中改回来就变成现在的时间了!!