Question

用C语言，读取一个文件最后8个字符，存储到一个数组中。如何实现？

Answer 1

#include<stdio.h>
#include<stdlib.h>
#include<conio.h>
void main()
{

FILE *fp;
char a[9];
fp=fopen("你要操作的文件的位置","r");
fp=fseek(fp,8L,2);
fgets(a,8,fp);
printf("%s",a);
fclose(fp);
}
不知道可不可以，你自己在去调试一下啊！

Answer 2

#include <stdio.h>
#include <stdlib.h>

int main() {
FILE *fp = NULL;
char buff[10] = {0};
fp = fopen("filepath", "r");
fseek(fp, -8l, SEEK_END)
fread(buff, sizeof(char), 8, fp);
......
}

差不多了吧！

Answer 3

char buf[8];

FILE * fp = fopen("a.x", "a+");

fseek(fp, -8, SEEK_END);
fread(buf, 1, 8, fp);
fclose(fp);

Answer 4

//---------------------------------------------------------------------------

#include <stdio.h>

int main(void)
{
FILE *fp=fopen("c:\\a.txt","r");
char st[9]={0};
fseek(fp,-8,SEEK_END);
fread(st,sizeof(char),8,fp);
fclose(fp);
puts(st);
return 0;
}
//---------------------------------------------------------------------------