Question

大家帮我解两道题、急求！！！ (x-1)/(x^2-5x+6)+(x-2)/(x^2-4x+3)+(x-3)/(x^2-3x+2)

还有一道：(1-4x)^2/2x+3*(4x^2+12x+9)/(4x-1)

拜托了！！！！！！！
(1-4x)^2/（2x+3）*(4x^2+12x+9)/(4x-1)

第二题应该是这样的、不好意思、要有过程！！！

Answer 1

(x-1)/(x^2-5x+6)+(x-2)/(x^2-4x+3)+(x-3)/(x^2-3x+2)
= (x-1)/{(x-2)(x-3)} + (x-2)/{x-1)(x-3)} + (x-3)/{(x-1)(x-2)}
= { (x-1)^2 + (x-2)^2 + (x-3)^2 } / { (x-1)(x-2)(x-3) }
= (x^2-2x+1+x^2-4x+4+x^2-6x+9) / { (x-1)(x-2)(x-3) }
= (3x^2-12x+14) / (x-1)(x-2)(x-3)

(1-4x)^2/(2x+3) * (4x^2+12x+9)/(4x^2-1)
= (4x-1)^2/(2x+3) * (2x+3)^2/(4x-1)
= (4x-1) * (2x+3)
= 8x^2+10x-3

Answer 2

一、(x-1)/(x^2-5x+6)+(x-2)/(x^2-4x+3)+(x-3)/(x^2-3x+2) =(x-1)/【（x-2)(x-3)】+(x-2)/【(x-1)(x-3)】+(x-3)/【(x-1)(x-2)】=[(x-1)^2+(x-2)^2+(x-3)^2/【(x-1)（x-2)(x-3)】=[(x-1)^2+(x-2)^2+(x-3)^2/【(x-1)（x-2)(x-3)】=(3x^2-12x+14)/【(x-1)（x-2)(x-3)】
二、(1-4x)^2/（2x+3）*(4x^2+12x+9)/(4x-1)=-(1-4x）*（2x+3）