Question

利用递归方法求5！（JAVA程序）

Answer 1

public class Test {
public static void main(String args[]) {
int x = 5;
int rs = Fac(x);

System.out.println("" + x + "! = " + rs);
}

public static long Fac(int x) { /*阶乘算法*/
if (x > 1)
return (x * Fac(x - 1)); /*递归*/
else
return 1;
}
}

Answer 2

public class DiGuiTest
{

/**
* @param args
*/
public static void main( String[] args )
{
DiGuiTest di = new DiGuiTest();
System.out.println( di.Function1( 5 ) );
// TODO Auto-generated method stub

}
//method
public int Function1( int a )
{
if( a == 1 )
return a;//递归结束条件
return a * Function1( a - 1 );//调用递归
}

}

Answer 3

public class Test
{
public static int method(int i)
{
if(i == 1)
{
return i;

}
else
{
return i* method(i - 1);

}

}

public static void main (String[] args)
{
System.out.println(method(5));
}

}

Answer 4

您好！！
public class Digui {
public static int digui(int n){
if(n==1)return 1;
else
return n*digui(n-1);
}
public static void main(String[] args) {
System.out.println(digui(5));
}
}

Answer 5

public class T{

public static void main(String args){

}

public static int F(int n){
if(n == 1){
return 1;
}
return n * F(n - 1);
}
}