y/(x+y)-x/(x-y)
4个回答
展开全部
y/(x+y)-x/(x-y)
=y(x-y) /(x+y)(x-y) -x(x+y) /(x+y) (x-y)
=[y(x-y) -x(x+y)] /(x+y) (x-y)
=[xy-y^2 -x^2-xy] /(x+y) (x-y)
=[-y^2-x^2] /(x+y) (x-y)
=-(x^2+y^2)/(x^2-y^2)
=y(x-y) /(x+y)(x-y) -x(x+y) /(x+y) (x-y)
=[y(x-y) -x(x+y)] /(x+y) (x-y)
=[xy-y^2 -x^2-xy] /(x+y) (x-y)
=[-y^2-x^2] /(x+y) (x-y)
=-(x^2+y^2)/(x^2-y^2)
本回答被提问者采纳
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
展开全部
y / (x+y) - x / (x-y)
= y (x-y) / (x² - y²) - x (x+y) / (x² - y²)
= [y (x-y) - x (x+y)] / (x² - y²) [y (x-y) - x (x+y)] = xy - y² - x² - xy = - y² - x²
= - (x² + y²) / (x² - y²)
= y (x-y) / (x² - y²) - x (x+y) / (x² - y²)
= [y (x-y) - x (x+y)] / (x² - y²) [y (x-y) - x (x+y)] = xy - y² - x² - xy = - y² - x²
= - (x² + y²) / (x² - y²)
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
展开全部
y/(x+y)-x/(x-y)={y(x-y)-x(x+y)}/x²-y²=xy-y²-x²-xy/x²-y²=-(y²+x²)/x²-y²
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
更多回答（2）
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
