Question

C语言.求一个4X4矩阵的对角线元素之和,并找出对角线元素中的最大值..

Answer 1

#include "stdio.h"
int main()
{
int shuzu[4][4];
int i;
int j;
int maxs;
int sum=0;
for (i=0;i<4;i++)
{
for (j=0;j<4;j++)
{
printf("输入%d行%d列的数值:",i,j);
scanf("%d",&shuzu[i][j]);
sum+=shuzu[i][j];
}
}
printf("你的输入结果如下:\n");
for (i=0;i<4;i++)
{
for (j=0;j<4;j++)
{
printf("%4d",shuzu[i][j]);
}
printf("\n");
}
maxs=shuzu[0][0];
for (i=0;i<4;i++)
{
if (maxs<shuzu[i][i])
{
maxs=shuzu[i][i];
}
}
printf("对角线的最大值是:%d\n",maxs);
printf("和为:%d\n",sum);
return 0;
}

Answer 2

#include "stdio.h"
int main()
{
int shuzu[4][4];
int i;
int j;
int maxs;
int sum=0;
for (i=0;i<4;i++)
{
for (j=0;j<4;j++)
{
printf("输入%d行%d列的数值:",i,j);
scanf("%d",&shuzu[i][j]);

}
}
printf("你的输入结果如下:\n");
for (i=0;i<4;i++)
{
for (j=0;j<4;j++)
{
printf("%4d",shuzu[i][j]);
}
printf("\n");
}
maxs=shuzu[0][0];
for (i=0;i<4;i++)
for(j=0;j<4;j++)
if(i==j||j+i==3)
{ sum+=shuzu[i][j];
if (maxs<shuzu[i][j])

maxs=shuzu[i][j];
}

printf("对角线的最大值是:%d\n",maxs);
printf("和为:%d\n",sum);
return 0;
}

Answer 3

void matrix(double a[][4],double &maxVal,double &diagonalSum)
{
for (int i=0;i<4;i++)
{
int val = a[i][i];
diagonalSum +=val;
if (val>maxVal )
{
maxVal = val;
}
}
}

Answer 4

int a[4,4],sun;
for(;;)
{
sun+=a[i,j];
i++;j++;
}
这是求和的

Answer 5

代码:

运行结果: