Question

求s=1=1/(2*2)+1/(3*3)+1/(4*4)+1/(5*5)+.....+1/(n*n)的近似值。用C语言编写

Answer 1

#include "stdafx.h"
#include "stdafx.h"
#include "math.h"
#include "stdio.h"

void main()
{
float s=0;
printf("please input a number to count s=1+1/(2*2)+...+1/(n*n), n<100 :");
int n=getchar()-'0';
for(int i=1;i<=n;i++)
s=s+1.0/(i*i);
printf("the result is: %f\n",s);
}

已经运行过了，没问题~~

Answer 2

给你写段语句块做参考吧

int n，i；
int s=0；
for(i=1;i<n;i++)
s=s+1/(i*i);

Answer 3

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