Question

用BAT或者VBS 批量替换文件夹下任意文件名字包含.ABC的字符为空

文件夹下面 文件名字当中如果含有 .ABC 把所有包含.ABC的替换为空

谢谢大侠们

Answer 1

这是BAT的,试过,可行
@echo off
setlocal enabledelayedexpansion
set file=
set /p file= 请输入要操作的文件名称(包括扩展名)：
set "file=%file:"=%"
for %%i in ("%file%") do set file=%%~fi
set replaced=
set /p replaced= 请输入即将被替换的内容：
set all=
set /p all= 请输入替换字符串：
for /f "delims=" %%i in ('type "%file%"') do (
set str=%%i
set "str=!str:%replaced%=%all%!"
echo !str!>>"%file%"_tmp.txt
)
copy "%file%" "%file%"_bak.txt >nul 2>nul
move "%file%"_tmp.txt "%file%"
start "" "%file%"

Answer 2

@echo off
(for /f "delims=" %%i in ('dir /b /a-d^|findstr /c:".ABC"') do (
set "var="%%i""&call,set "var=%%var:.ABC=%%"
call,ren "%%i" %%var%%
))>nul

将删除.ABC。。。。

Answer 3

on error resume next
for each i in createobject("scripting.filesystemobject").getfolder(".").files
st=""
s=split(i.name,".ABC")
for n=0 to ubound(s)
st=st&s(n)
next
i.name=st
next