求达人帮帮忙,谢谢
1个回答
2014-08-20
展开全部
∠1=180-∠CAB/2-∠CEA
=180-∠CAB/2-(∠ACB/2+∠ABC)
=180-∠CAB/2-∠ACB/2-∠ABC
=180-(∠CAB/2+∠ACB/2+∠ABC/2)-∠ABC/2
=180-180/2-∠ABC/2
=90-∠ABC/2
=90-∠GBO
=∠2
=180-∠CAB/2-(∠ACB/2+∠ABC)
=180-∠CAB/2-∠ACB/2-∠ABC
=180-(∠CAB/2+∠ACB/2+∠ABC/2)-∠ABC/2
=180-180/2-∠ABC/2
=90-∠ABC/2
=90-∠GBO
=∠2
追答
亲给个好评吧亲
,快一点
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询