Question

C语言；请编写一个程序，计算1-1/2+1/3-………+1/99-1/100，求原创

Answer 1

#include<stdio.h>
main()
{
float sum=0.0;
int i,n;
float a=-1.0;
printf("sum 1-1/2+1/3....");
scanf("%d",&n);
for(i=1;i<=n;i++)
{a=-a;
sum=sum+a/i;
}
printf("sum=%f",sum);
}

Answer 2

#include<stdio.h>
int main()
{
int sign=1;
double term,sum=1.0,deno=2.0;
for(;deno<=100;deno++)
{
sign=-sign;
term=sign/deno;
sum+=term;
}
printf("%f\n",sum);
return 0;
}
在vc里运行过了。可用。

Answer 3

nclude<stdio.h>
int main()
{
int sign=1;
double term,sum=1.0,deno=2.0;
for(;deno<=100;deno++)
{
sign=-sign;
term=sign/deno;
sum+=term;
}
printf("%f\n",sum);
return 0