2个回答
2011-05-08
展开全部
y=f(x)图像的一条对称轴是直线x=π/8,对称轴与图像交点应为图像最高点或最低点,把其代入y=sin(2x+φ),y=sin(2*π/8+φ)=sin(π/4+φ)=1或-1,
0<φ<π,π/4<π/4+φ<5π/4,π/4+φ=π/2,φ=π/4
y=f(x)=sin(2x+π/4)
当0=<x<=π时,π/4=<2x+π/4<=2π+π/4,当2x+π/4=π/2,即x=π/8时y取最大值1,
当2x+π/4=3π/2,即x=5π/8时,y取最小值-1
0<φ<π,π/4<π/4+φ<5π/4,π/4+φ=π/2,φ=π/4
y=f(x)=sin(2x+π/4)
当0=<x<=π时,π/4=<2x+π/4<=2π+π/4,当2x+π/4=π/2,即x=π/8时y取最大值1,
当2x+π/4=3π/2,即x=5π/8时,y取最小值-1
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询