
工程力学题目c图,求解
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解答 C图
(1)求支座反力:
无X方向荷载,RAX =0,
题目的200未标明长度单位,假设为200cm,即2m
ΣMB =0,-RAY.6m + (10kN/m).4m.2m =0
RAy ≈13.33kN(向上)
ΣMA =0, RBY.6m - (10kN/m).4m.4m =0
RBY ≈26.67kN(向上)
(2)求剪力及弯矩
截面1-1剪力Q1 = RAY = 13.33KN
截面2-2剪力Q2 = RAY -(10KN/m).2m = 13.33KN -20KN = -6.67KN
截面1-1弯矩M1 = RAY.2m =13.33KN.2m =26.66KN.m
截面2-2弯矩M2 = RAY.4m -(10KN/m).2m.1m =13.33KN.4m -20KN.m = 33.32KN.m
(1)求支座反力:
无X方向荷载,RAX =0,
题目的200未标明长度单位,假设为200cm,即2m
ΣMB =0,-RAY.6m + (10kN/m).4m.2m =0
RAy ≈13.33kN(向上)
ΣMA =0, RBY.6m - (10kN/m).4m.4m =0
RBY ≈26.67kN(向上)
(2)求剪力及弯矩
截面1-1剪力Q1 = RAY = 13.33KN
截面2-2剪力Q2 = RAY -(10KN/m).2m = 13.33KN -20KN = -6.67KN
截面1-1弯矩M1 = RAY.2m =13.33KN.2m =26.66KN.m
截面2-2弯矩M2 = RAY.4m -(10KN/m).2m.1m =13.33KN.4m -20KN.m = 33.32KN.m
追问
谢谢你。(^_^)
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