Question

c++一个类需要有两种xml序列化形式怎么办

class a{
public:
string name;
char a[10];
}将这个类用boost序列化为xml文件，第一次调用序列化时要求序列化name属性，第二次需要序列化name和a[10]，这该怎么办？

Answer 1

序列化或反序列化成一个字符串：方法一：序列化：public static string XMLSerialize<T(T entity){StringBuilder buffer = new StringBuilder();
XmlSerializer serializer = new XmlSerializer(typeof(T));
using (TextWriter writer = new StringWriter(buffer)){serializer.Serialize(writer, entity);}
return buffer.ToString();}反序列化：
public static T DeXMLSerialize<T(string xmlString){T cloneObject = default(T);
StringBuilder buffer = new StringBuilder();
buffer.Append(xmlString);
XmlSerializer serializer = new XmlSerializer(typeof(T));
using (TextReader reader = new StringReader(buffer.ToString())){Object obj = serializer.Deserialize(reader);
cloneObject = (T)obj;}
return cloneObject;}方法二：/// <summary
/// 对象序列化成 XML String
/// </summary
public static string XmlSerialize<T(T obj){string xmlString = string.Empty;
XmlSerializer xmlSerializer = new XmlSerializer(typeof(T));
using (MemoryStream ms = new MemoryStream()){xmlSerializer.Serialize(ms, obj);
xmlString = Encoding.UTF8.GetString(ms.ToArray());}return xmlString;}
/// <summary
/// XML String 反序列化成对象
/// </summary
public static T XmlDeserialize<T(string xmlString){T t = default(T);
XmlSerializer xmlSerializer = new XmlSerializer(typeof(T));
using (Stream xmlStream = new MemoryStream(Encoding.UTF8.GetBytes(xmlString))){using (XmlReader xmlReader = XmlReader.Create(xmlStream)){Object obj = xmlSerializer.Deserialize(xmlReader);
t = (T)obj;}}return t;}如果要序列化到一个文件，则使用FileStream就可以了如：string strFile = @c:/book.xml;
using (FileStream fs = new FileStream(strFile, FileMode.Create)){
XmlSerializer formatter = new XmlSerializer(typeof(T));
formatter.Serialize(fs, entity);}附：其实还可以直接用SringWriter
StringBuilder sb = new StringBuilder();
System.IO.StringWriter writer = new System.IO.StringWriter(sb);