Question

使用Spring Data JPA+hibernate持久化对象时报异常

异常描述:javax.validation.UnexpectedTypeException: HV000030: No validator could be found for type: java.lang.Integer.
保存一个User对象
User类

@Entity
@Table(name="t_front_user")
@Cache(usage=CacheConcurrencyStrategy.NONSTRICT_READ_WRITE, region="com.jxufe.oec.entity.main.User")
public class User implements Idable<Long> {

public static final Integer STATUS_DISABLED = 0;
public static final Integer STATUS_ENABLED = 1;

@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private Long id;

@NotBlank
@Length(max=32)
@Column(length=32, nullable=true)
private String realname;

@NotBlank
@Length(max=32)
@Column(length=32, nullable=false, unique=true, updatable=false)
private String username;

@Column(length=64, nullable=false)
private String password;

@Transient
private String plainPassword;

@Column(length=32, nullable=false)
private String salt;

@Length(max=32)
@Column(length=32)
private String phone;

@Email
@Length(max=128)
@Column(length=128)
private String email;

/**
* 使用状态disabled，enabled
*/
@NotNull
@Length(max=16)
@Column(length=16, nullable=false)
private Integer status = STATUS_ENABLED;

/**
* 帐号创建时间
*/
@Temporal(TemporalType.TIMESTAMP)
@Column(updatable=false)
private Date createTime;
测试方法
User user=new User();
user.setUsername("zxw2476");
user.setPassword("123456");
user.setRealname("张三");
user.setPhone("18720085474");
user.setEmail("1414628406@qq.com");
user.setStatus(0);
user.setCreateTime(new Date());
userService.saveOrUpdate(user);
错误定位在最后保存方法中

Answer 1

@NotNull
@Length(max=16)
@Column(length=16, nullable=false)
private Integer status = STATUS_ENABLED;

integer 类型没有这种校验类型，所以错了。

追问

那是不是应该去掉@NotNull注解？

追答

@notnull 和@length都去掉。