（X+y+1）^2一（X+y一3）^2的答案
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（X+y+1）^2一（X+y一3）^2
= [(x+y+1)+(x+y-3)] X [(x+y+1) - (x+y-3)]
= (x+y+1+x+y-3) X (x+y+1-x-y+3)
= 4(2x+2y-2)
=8x+8y-8
求采纳噢💅
= [(x+y+1)+(x+y-3)] X [(x+y+1) - (x+y-3)]
= (x+y+1+x+y-3) X (x+y+1-x-y+3)
= 4(2x+2y-2)
=8x+8y-8
求采纳噢💅
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