Question

C语言简单问题，求大家帮忙看看！

写一个SUM函数，对实型数组中所有元素求和

float sum(float *array,int number);

写一个AVERAGE函数，求实型数组中所有元素的平均值

float average(float *array,int number)

写主程序调用这2个函数，并输出结果

这道题该怎么做呀？
求代码！！！

Answer 1

#include <stdio.h>
float sum(float *array, int number);
float average(float *array, int number);

void main()
{
float a[10];
int i;
printf("请输入数组:\n");
for(i=0;i<10;i++)
{
scanf("%f",&a[i]);
}

printf("和为%f\n",sum(a,10));
printf("平均数为:%f\n",average(a,10));
}

float sum(float *array, int number)
{
int j;
float s=0;
for(j=0;j<number;j++)
s += array[j];
return s;
}

float average(float *array, int number)
{
int j;
float s=0, aver=0;
for(j=0;j<number;j++)
s += array[j];
aver = s/number;
return aver;
}

Answer 2

float sum(float *array,int number)
{
int i = 0;
float result = 0;

for (i = 0; i < number; i++)
{
result = *(array + i) + result;
}

return result;
}

float average(float *array,int number)
{
int i = 0;
float result;

for (i = 0; i < number; i++)
{
result = result + *(array + i);
}
return result / number;
}

追问

大虾。 主函数在哪呢？

追答

#include
float sum(float *array,int number)
{
int i = 0;
float result = 0;

for (i = 0; i < number; i++)
{
result = *(array + i) + result;
}

return result;
}

float average(float *array,int number)
{
int i = 0;
float result;

for (i = 0; i < number; i++)
{
result = result + *(array + i);
}
return result / number;
}
void main()
{
int i = 0;
float result = 0;
float a[] = {3.3, 4.4, 5.5, 6.6, 7.7};
result = sum(a, 5);
cout << "总和" << result;
result = average(a, 5);
cout << "平均" << endl;
}