Question

如何用一段简单的java代码获取302跳转前网址的cookie

RT

Answer 1

参考：
public static void main(String[] args) {

try {

String url = "http://www.twitter.com";

URL obj = new URL(url);
HttpURLConnection conn = (HttpURLConnection) obj.openConnection();
conn.setReadTimeout(5000);
conn.addRequestProperty("Accept-Language", "en-US,en;q=0.8");
conn.addRequestProperty("User-Agent", "Mozilla");
conn.addRequestProperty("Referer", "google.com");

System.out.println("Request URL ... " + url);

boolean redirect = false;

// normally, 3xx is redirect
int status = conn.getResponseCode();
if (status != HttpURLConnection.HTTP_OK) {
if (status == HttpURLConnection.HTTP_MOVED_TEMP
|| status == HttpURLConnection.HTTP_MOVED_PERM
|| status == HttpURLConnection.HTTP_SEE_OTHER)
redirect = true;
}

System.out.println("Response Code ... " + status);

if (redirect) {

// get redirect url from "location" header field
String newUrl = conn.getHeaderField("Location");

// get the cookie if need, for login
String cookies = conn.getHeaderField("Set-Cookie");

// open the new connnection again
conn = (HttpURLConnection) new URL(newUrl).openConnection();
conn.setRequestProperty("Cookie", cookies);
conn.addRequestProperty("Accept-Language", "en-US,en;q=0.8");
conn.addRequestProperty("User-Agent", "Mozilla");
conn.addRequestProperty("Referer", "google.com");

System.out.println("Redirect to URL : " + newUrl);

}

BufferedReader in = new BufferedReader(
new InputStreamReader(conn.getInputStream()));
String inputLine;
StringBuffer html = new StringBuffer();

while ((inputLine = in.readLine()) != null) {
html.append(inputLine);
}
in.close();

System.out.println("URL Content... \n" + html.toString());
System.out.println("Done");

} catch (Exception e) {
e.printStackTrace();
}

}

Answer 2

只能获取Header头的值，然后用一个算法提取cookie即可