化简cos(α-π/2)/sin(5π/2+α)·sin(π-α)·cos(2π-α)
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化简[cos(α-π/2)]/[sin(5π/2+α)sin(π-α)cos(2π-α) ]
原式=[cos(π/2-α)]/[sin(2π+π/2+α)sin(π-α)cos(2π-α)]
=(sinα)/[sin(π/2+α)sinαcosα)]
=(sinα)/[(-cos²α)sinα]=1/(-cos²α)=-sec²α
原式=[cos(π/2-α)]/[sin(2π+π/2+α)sin(π-α)cos(2π-α)]
=(sinα)/[sin(π/2+α)sinαcosα)]
=(sinα)/[(-cos²α)sinα]=1/(-cos²α)=-sec²α
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